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5n^2+12n-44=0
a = 5; b = 12; c = -44;
Δ = b2-4ac
Δ = 122-4·5·(-44)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-32}{2*5}=\frac{-44}{10} =-4+2/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+32}{2*5}=\frac{20}{10} =2 $
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